an ideal monatomic gas is taken round the cycle ABCDA as shown. calculate the work done during the cycle
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Answered by
96
work done is given by area between the pv graph
area=(2p-p) x (2v-v)
area =pv
as it is clockwise
work done is negative
work done=-pv
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area=(2p-p) x (2v-v)
area =pv
as it is clockwise
work done is negative
work done=-pv
vote brainliest
Answered by
34
Work done from A - B is Zero (isochoric process).
W.d from B-c= p.dv=-2p[dv](upper limit =2v; lower limit =v)
We get- (-2pv)[note- p is negative for clock wise direction]
W.d from c-d =0(isochoric process)
W.d from d-a= pdv= p.[dv](upper limit =v; lower limit=2v.) [Note- p is positive for anticlockwise direction]
By integration-
We get = ( pv)
Than total work done=0+(-2pv)+0+(pv)
=-pv
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