An ideal refrigerator has a freezer at a temperature of 13ºC.
The coefficient of performance of the engine is 5. The
temperature of the air (to which heat is rejected) is
(a) 320ºC (b) 39ºC
(c) 325 K (d) 325ºC
Answers
Answered by
0
Explanation:
Given : T
H
=−13
o
C β=5
∴ T
H
=273−13=260 K
Coefficient of performance β=
T
H
−T
L
T
H
∴ 5=
260−T
L
260
⟹T
L
=312 K
Thus temperature of air T
L
=312−273=39
o
C
Similar questions