Question

An ideal solution contains two volatile liquids 100 200 . O o a p torr and b p torr if mixture contain 1mole of a and 4 mole of b then total vapour pressure of the distillate is:

Answer 1

Explanation:

· o —m ; ~Z ~ 2 number of a particles at 6 = I ^T™TT7T ; b .... only (B) Spectrum of atom of iron containing one electron only ...... Abnormal melting point & boiling ...

Answer 2

The total vapour pressure of the distillate is 180 torr

Explanation:

According to Raoult's law, the vapor pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the vapor pressure of that component in the pure state.

$p_1=x_1p_1^0$ and $p_2=x_2P_2^0$

where, x = mole fraction

in solution  

$p^0$ = pressure in the pure state

According to Dalton's law, the total pressure is the sum of individual pressures.

$p_{total}=p_1+p_2$$p_{total}=x_Ap_A^0+x_BP_B^0$

$x_{a}=\frac{\text {moles of a}}{\text {moles of a+moles of b}}=\frac{1}{1+4}=0.2$

$x_{b}=1-x_{a}=1-0.2=0.8$,  

$p_{a}^0=100torr$

$p_{b}^0=200torr$

$p_{total}=0.2\times 100+0.8\times 200=180torr$

Thus the total vapour pressure of the distillate is 180 torr

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