An image 2/3 of the size of an object is formed by aconvex lens at a distance of 12cm from it. Find the focal length of the lens
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1/f(focal length)=1/v-1/u
by putting the value,
1/f=1/12-(-1/8)
=1/12+1/8
=2+3/24
=5/24
therefore,
f=24/5
f=4.8cm
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