Question

An image 5cm in height is placed at a distance of 15cm in front of a convex mirror of radius of curvature of 40cm.Find the position of the image and nature of the image.​

Answer 1

40 × 5 + 15 you can find it with

Answer 2

Answer:

Formula:

v

1

+

u

1

=

f

1

Given,

v

1

+

(−20)

1

=

15

1

v

1

=

60

7

⇒v=

7

60

v=8.57≈8.6cm

The image is formed behind the mirror at a distance of 8.6 cm

m=

h

1

h

2

=−

u

v

→

5

h

2

=−

20

8.57

∴h

2

=2.175 cm

Thus the image is 2.175 cm high, virtual and erect.

Hence, this is the answer.

Step-by-step explanation:

hope it help you