Question

an image of an object made on that object which is situated 30cm distance from the pole on main axis of concave mirror​

Answer 1

Answer:

Height of object, h o

=5cm, object distance u=−30cm, focal length f=−20cm

Now, from mirror formula : f1

= v1 + u1

v1= f1 − u1

= 20−1+30

1=− 61

1

v=−60cm - image distance

Magnification, m=u-v

=−30−60

=−2

Size of image, h i

=m(h o)=−2(5)=−10 cm