Question

An immersion heater has a rating of 2 kW, 220 V.
While in use, calculate
(i) current passing through it and
(ii) its resistance.​

Answer 1

P=VI

2000=220XI

2000/220=I

I=9.09A

V=IR

220/9.09=R

R=24.2Ω

Answer 2

Answer:

P=VI

2000=220×I

2000/200=I

I=0.09A

V=IR

220/9.09=R

R= 24.2 Ω