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An immersion heater rated 1.5 kW is used to heat 10 kg of water. Calculate the time taken in raising the temperature of the water by 32°C. Specific heat capacity of water is 4200 J/kg °C.
please answer it fast with solution please please
Answers
Answered by
3
Answer:
Given:
heat capacity of water = 4200 J kg–1 K–1.
Formula used:
ΔQ=MCΔT
ΔQ=heat exchange
ΔT=tempeature change
M=mass
C=heat capacity
Heat given by heater = heat taken by water
0.8× 1000× t=20× 4200× (35-10)
t=2625 s=43.75 minutes
Answered by
0
Answer:
Explanation:
Given:
heat capacity of water = 4200 J kg–1 K–1.
Formula used:
ΔQ=MCΔT
ΔQ=heat exchange
ΔT=tempeature change
M=mass
C=heat capacity
Heat given by heater = heat taken by water
0.8× 1000× t=20× 4200× (35-10)
t=2625 s=43.75 minutes
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