Question

an impulse force of 100 n acts on a body of mass 0.5 kg for 1 second what is the change in kinetic energy​

Answer 1

Answer:-

ΔK.E. = 10KJ

Explanation:-

Given:

• Impulse(J) = 100N
• time (t) = 1 sec
• mass(m) = 0.5kg

To Find:

Change in the kinetic energy

Solution:

W.k.t

J = mat

$J = m \times \dfrac{ΔV}{Δt} \times t$

$100 = 0.5 \times \dfrac{ΔV}{1} \times 1$

$ΔV = \dfrac{100}{0.5}$

$ΔV = 200 m/s$

Now,

ΔK.E. = ¹/² mΔv²

$ΔK.E. = \dfrac{1}{2} (0.5) {(200)}^{2}$

$ΔK.E. = \dfrac{1}{2} (0.5) (40000)$

$ΔK.E. = 10000J$

$ΔK.E. = 10KJ$