An impulse "I" given to a body changes its velocity from "v1 to v2" . The increase in the kinetic energy of the body is given by
Answers
Answered by
139
I = impulse given to a body of mass m
= change in the momentum of the body
= mv2 - mv1
Increase in kinetic energy of the body
ΔKE = 1/2 mv2² - 1/2 mv1²
= 1/2 m (v2+v1) (v2-v1)
= I * (v2+v1)
= change in the momentum of the body
= mv2 - mv1
Increase in kinetic energy of the body
ΔKE = 1/2 mv2² - 1/2 mv1²
= 1/2 m (v2+v1) (v2-v1)
= I * (v2+v1)
kvnmurty:
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Answered by
17
Answer:
I/2(v2+v1)
Explanation:
Change in kinetic energy =1/2mv2square-1/2mv1square m/2(v2square-v1square) (change in momentum is impulse) m/2(v2-v1)(v2+v1) =I/2(v2+v1)
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