Physics, asked by mishayam, 8 months ago

An impulsive force acting on a particle increases the kinetic energy of the particles by 100%. The
increase in the momentum is
A) 10%
C) 40%
B) 70%
D) 100%

Answers

Answered by lakshj186
0

Answer

A) 100 percent

If you will read the question U will understand it

Answered by aburaihana123
0

An impulsive force acting on a particle increases the kinetic energy of the particles by 100% then increase in the momentum is 40%

Explanation:

Linear momentum    P = √2mk

Final kinetic energy k_{f} = 2k

So final momentum p_{f}  = \sqrt{2mk_{f} }

= √4mk

Percentage change in momentum

\frac{P_{f} - P }{P}  × 100

\frac{\sqrt{4mK} - \sqrt{2mK}  }{\sqrt{2mK} }  × 100

Therefore,

\frac{P_{f} - P }{P} × 100 = \frac{\sqrt{4} -\sqrt{2} }{\sqrt{2} } × 100

= 41 .4 %

Final answer

An impulsive force acting on a particle increases the kinetic energy of the particles by 100% then increase in the momentum is 40%

#SPJ3

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