Question

An inclined plane makes an angle = 45° with horizontal. A stone
is projected normally from the inclined plane, with speed u m/s at
t=0 sec. x and y axis are drawn from point of projection along and
normal to inclined plane as shown. The length of incline is sufficient
for stone to land on it and neglect air friction. Match the statements
given in column 1 with the results in column II. (g in column II is
acceleration due to gravity.)
Column 1
Column II
220
(A) The instant of time at which velocity of stone is
parallel to x-axis
(B) The instant of time at which velocity of stone
makes an angle 8 = 45° with positive x-axis.
in clockwise direction
(C) The instant of time till which (starting from t = 0)
3
component of displacement along x-axis become half
the range on inclined plane is
(D) Time of flight on inclined plane is
U
(s)
2​

Answer 1

Answer:

Step-by-step explanation:

=> Time of flight on inclined plane is:

T = 2u / g cos 45  

= 2u / g cos 45 * 2√2u/g

So, D￫P

=> An inclined plane makes an angle = 45° with horizontal. Thus, its velocity is horizontal:

time = u sin 45 / g = u/ √2 g

So, B➝s

=> The instant of time till which (starting from t = 0) component of displacement along x-axis become half, the range on inclined plane is:

= 1/√2 T = 2u/g

So, C ￫ q

Ans. (C) The instant of time till which (starting from t = 0)

3  component of displacement along x-axis become half  the range on inclined plane