Question

an inclined plate 2 m long and 1m wide lies with its length inclined at 45 to the surface of water and the nearest edge 1m below it if the specific weigth of water is 1000kg/m3 then tge total presurre on the olate is appromximantely

Answer 1

Answer:

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Explanation:

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Answer 2

Given:-

length of plate, L=2 m

width of plate, b=1 m

angle of inclination, $\theta$=$45^{0}$

density of water, $\rho=1000kg/m^{3}$

distance of plate upper edge from free surface=1 m

To Find:-

hydrostatic force on the plate

Explanation:-

$\text{Area of the plate, }A=L\times d=2\times1=2m^{2}\\\\\text{distance of plate CG from free surface of liquid, }\bar{x}=1+(1\times sin45^{0})=1.707m\\\\\text{Hydrostatic force on the plate is given by:-}\\\\F_{H}=\rho\times g\times A\times\bar{x}=1000\times9.81\times2\times1.707=33491.34N=33.491kN$