Question

An incompressible fluid flows steadily through a cylindrical pipe which has radius 2r at point a and radius r at ppint b frther alonv the flow direction

Answer 1

Answer:

We know, for the fluid flowing through the nonuniform pipe the velocity of a fluid is inversely proportional to the area of cross-section.

Hence, according to problem given, if v1,v2 are the velocities at A and B and a1,a2 are the area of cross-sections at A and B, then

v1v2=a2a1

Here, an in-compressible fluid flows steadily through a cylindrical pipe which has radius 2R at point A and radius R at point B farther along the flow direction, hence

v2=a2a1v1=πR2π(2R)2(v) 

∴v2=4v  

hope it's help you