An incompressible liquid of density rho is enclosed with two frictionless pistons one of cross sectional area A and the other of 4A. When the narrow piston moves in by a distance h, the wider piston moves out by a distance.
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The liquid will move a distance of h/4
Explanation:
Since the liquid is in-compressible , and it is a single system, therefore the volume will be conserved .
That is the reduction in the volume of liquid in the 4A section will be = Area x distance moved by the liquid ( lets suppose"y" )
= 4A x y
will be equal to the increase in the volume of liquid in area A
= A h
4A y = A h
h/4 = y = so it will move a distance of h/4
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