Question

An increase in intensity level of one decibel implies an increase in intensity of:
(a. 1%
b. 3.01%
c. 26%
d. 0.1%)​

Answer 1

Answer:

2.6%

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Answer 2

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PHYSICS

An increase in intensity level of 1 dB implies an increase in the intensity by (given antilog

10

0.1=1.2589)

December 20, 2019avatar

Hetal Punjabi

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VIDEO EXPLANATION

ANSWER

Given, IL

2

−IL

1

=1 dB

1=10log

10

[

Io

I

2

]−10log

10

[

Io

I

1

]

where I

1

and I

2

are the initial and final intensity of sound

respectively such that the increase in

intensity level is 1 dB.

∴1=10[log

10

[

I

o

I

2

]−10log

10

[

I

o

I

1

]]

∴1=10

⎣

⎢

⎢

⎢

⎡

log

10

⎣

⎢

⎢

⎢

⎡

I

o

I

1

I

o

I

2

⎦

⎥

⎥

⎥

⎤

⎦

⎥

⎥

⎥

⎤

∴1=10[log

10

[

I

o

I

2

∗

I

1

I

o

]]

∴1=10log

10

[

I

1

I

2

]

∴0.1=10log

10

[

I

1

I

2

]

antilog0.1=

I

1

I

2

I

2

=(antilog0.1)×I

1

I

2

=1.26×I

1

∴ Increase in intensity that produces an increase in intensity level by 1 dB

=I

2

−I

1

=1.26I

1

−I

1

=(1.26−1)I

1

=0.26I

1

or 26% of I

1

Hence, when the intensity of sound increases by 26%, the intensity level increases by 1 dB .