Question

An indicator from an engine has a length of 100mmhas a length of 100mm and area of 2000mm2 if the indicator pointed deflects 10mm for a pressure increment of 2 bar the mep is

Answer 1

Answer:

IC Engine Questions and Answers – Comparison of Two Stroke S.I. and C.I. Engines – 2

Explanation:

please mark me Isa brilliant

Answer 2

Therefore Mean Effective Pressure MEP of the engine is 4 bar.

Given:

Length of engine = L = 100 mm

Area of the engine = A = 2000 mm²

Deflection of the indicator = d = 10 mm

Pressure increment = 2 bar

To Find:

Mean Effective Pressure ( MEP )

Solution:

We can simply solve this numerical problem by using the following process.

Given that

Length of engine = L = 100 mm = 0.1 m

Area of the engine = A = 2000 mm² = 2 × 10⁻³ m

Deflection of the indicator = 10 mm = 10 × 10⁻³

Pressure increment = 2 bar = 2 × 10⁵

Now all the parameters are in SI units.

Mean Effective Pressure is given by,

⇒ MEP = ( P × A )/( L × d )

⇒ MEP = ( 2 × 10⁵ × 2 × 10⁻³ ) / ( 10⁻¹ × 10 × 10⁻³ )

⇒ MEP = ( 2 × 10⁵ × 2 )

⇒ MEP = 4 × 10⁵

⇒ MEP = 4 bar

Therefore Mean Effective Pressure MEP of the engine is 4 bar.

#SPJ2