An individual is nearsighted his near point is 13 cm and far point is 50 cm what lens power is needed to correct nearsightedness what length when lenses are in use what is the persons near.
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Lens power needed is -2D, and the near point is 13cm
Near point = N.P. = 13cm. (Given)
Far point = F.P. = 50cm. = 0.5m (Given)
Power of the lens to correct nearsightedness, -
P = 1/f
= 1/ FP - 1/Object
= 1/ 0.5 - 1/∞
= - 2D
Since, it is mentioned that he is suffering from nearsightedness, which is only the far point and not the near point,
Therefore, when the lenses will be in use, near point will be 13cm only.
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