Math, asked by sambantham0901, 1 month ago

An individual uses the following gambling system at Las Vegas. He bets $1 that
the roulette wheel will come up red. If he wins, he quits. If he loses then he makes
the same bet a second time only this time he bets $2; and then regardless of the
outcome, quits. Assuming that he has a probability of 1
2 of winning each bet, what
is the probability that he goes home a winner? Why is this system not used by
everyone?

Answers

Answered by tulidebnath1983
1

Answer:

P(Winning) = 0.5 P(Losing) =0.5 P(Goes home as winner ) = 0.5 + 0.5*0.5 = 0.75 Expected value of the bet = 2*0.5+(-0.5+4*.5 + (-0.5-2*.5)) Either he wins $2 in the first bet and quits Or he loses the first bet and wins 4$ in the second...

Answered by bvchratnakumari1988
0

Answer:

kinetic energy is minimum, potential energy is maximum.

In SHM, kinetic energy is maximum at mean position and zero at the extreme positions while potential energy is zero at mean position and maximum at the extreme positions.

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