An individual with cd genes is crossed with wild type `++`. On test crossing `F_(1)` hybrid, the progeny was `+c 105, +d 115, cd 880 and ++ 900`. Distance between cd genes is
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Since, recombination frequency,
=No.of recombinations/Total no.of property *100
= 115+108/115+105+900+880 *100
=11 m units.
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