Question

An induced EMF of 20 V exists in a coil when the current coil changes at a rate of 40 A/s. What is the self-inductance of the coil?

Answer 1

Answer:

0.5 H.

Explanation:

The relation between emf(e) and self inductance (L) and change in current is given by,

e = L*($\frac{di}{dt}$)

$\frac{di}{dt}$ = 40A/s and e = 20 V

hence by the above relation it's value is L= 20/40 =0.5 H