Question

An induction coil has 1000000 turns . the number of magnetic field lines through it changes from 0.004 wb to 0 in 0.01,le, then what is the average induced electromotiv force on the coil during this time?

Answer 1

Answer:

0.4*10^6 volt

Explanation:

Hello

As per given data

N(no. of turns in the coil)=1000000

p1(initial magnetic field line)=0.004 Wb

p2(final magnetic field line)= 0 Wb

d(t) = 0.01 s

so as per formula EMF= -N d(p)/d(t)= - 10^6*(0-0.004)/0.01

                                                          =0.4*10^6

May this explanation will help you

THANK YOU