Question

An inductive coil has a resistance of 100 Ω. When an a.c. signal of requency 1000 Hz is fed to the coil, the applied voltage leads the current by 45°. What is the inductance of the coil ?(a) 10 mH(b) 12 mH(c) 16 mH(d) 20mH

Answer 1

$<b>$

d) 20mH

Answer 2

Answer:

Explanation:

Resistance = 100 Ohm

Frequency(f) = 1000 Hz

Phase Angle = 45°

= Cos(phase angle) = Xl/R

= Cos(45°) = Xl/100

= Xl = 100 Ohm

Thus,

w = 2×π×f

w = 2x3.14x1000

w = 6280 rad/s

Thus,

Xl = wL

L = Xl/w

L = 100/6280

L = 0.01592

L = 15.92mH