An inductive coil with impedance Z = (5+j10) Ohm. Its conductance will be
Answers
Answer:
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Answer:
Conductance = 0.04 mho
Explanation:
The conductance of an inductive coil is given by the formula:
Conductance (G) = 1 / Impedance (Z)
Given that the impedance of the coil is Z = (5 + j10) ohm, we can calculate the conductance as follows:
G = 1 / (5 + j10) = 1 / (5 + j10) * (5 - j10) / (5 - j10) = (1 / (5^2 + 10^2)) + (j / (5^2 + 10^2)) = 0.04 - j0.08
Conductance is measured in mhos (also known as Siemens), which is the reciprocal of ohms. The imaginary component is not a physical value and will be dropped. Therefore, the conductance of the inductive coil is:
G = 0.04 mho