Physics, asked by nancy2228, 19 days ago

An inductor L having resistance R and a capacitor of capacitance C are connected to an alternating source of e.m.f. The quality factor of the circuit is​

Answers

Answered by kavitahari04
0

Answer:

the equally is equation

Answered by Anonymous
2

The quality factor of the circuit is Q= 1/R×( L/C )

The quality factor is the energy stored per unit cycle in the LCR circuit to the energy dissipated in one cycle.

Therefore, the higher the quality factor higher the energy stored in one cycle.

In the LCR circuit,

Quality factor = voltage across L or C/ total applied voltage

Q= wLi/Ri

where L is inductance, R is resistance, i is current

w= 1/√LC

Q= 1/R×√( L/C )

Therefore, the quality factor of the circuit is

Q= 1/R×( L/C )

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