Question

An inductor of inductance 50H and a resister of resistance 30 Ω is connected to a d.c. source in series. Find the time in which the current reaches to half of maximum current in the circuit.
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Answer 1

Answer: This may help you

Explanation:

Current in circuit at steady state = 102

=0.2A=I

0

​

Now, decay of current;

I=I

0

​

e

−

τ

t

​

as I=

e

1

​

I

0

​

∴

e

1

​

I

0

​

=I

0

​

e

−

τ

t

​

e

−1

=e

−

τ

t

​

or−1=−

τ

t

​

⇒t=τ=

R

L

​

=5s