Question

An inductor supplied with 50v ac with a frequency of 10 khz passes a current of 7.96ma.The value of inductor is

Answer 1

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➡V= IZ

V= IZ Z=V/I\

V= IZ Z=V/I\ Z= 50/ .00796

V= IZ Z=V/I\ Z= 50/ .00796 = 6281 ohms

V= IZ Z=V/I\ Z= 50/ .00796 = 6281 ohms impediance(Z) for an inductor = 2pi f L

V= IZ Z=V/I\ Z= 50/ .00796 = 6281 ohms impediance(Z) for an inductor = 2pi f L 6281 = 2 pi f L

V= IZ Z=V/I\ Z= 50/ .00796 = 6281 ohms impediance(Z) for an inductor = 2pi f L 6281 = 2 pi f L L = 6281/(2(3.141)( 10 x10^3))

V= IZ Z=V/I\ Z= 50/ .00796 = 6281 ohms impediance(Z) for an inductor = 2pi f L 6281 = 2 pi f L L = 6281/(2(3.141)( 10 x10^3)) 9.996 x 10^-2 H

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Answer 2

An inductor is a passive electrical component that resists sudden current changes. Inductors are also referred to as coils or chokes. L is the electrical symbol for an inductor.

Inductors work by temporarily storing energy in an electro-magnetic field and then releasing it back into the circuit to slow down current surges or spikes.

Surface mount (SM) inductors are soldered to pads on the top of a printed circuit board (PCB) and then reflow soldered. Through-hole (TH) inductors are wave soldered on the backside after being mounted on the top of a PCB with the leads fed through via holes in the board.

Given:

Voltage (V) = 50 V

Frequency (f) = 10kHz

Current (I) = 7.96mA

To find:

The value of the inductor

Solution:

X(L) = V ÷ I

= 50/(7.6*10^-3)

= 6.54 kΩ

⇒ 2пfL = 6.54

⇒ L = 6.54 / (2п*10*10^3)

⇒ L = 1.041 mH ≈ 1 mH

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