Question

an industrial bucket is of depth 3m with with the upper and lower diameter as 4 m and 2 m respectively. the amount of water it can hold is​ ? . options are a) 20cu.m b) 22cu.m c) 24cu.m d) none of these

Answer 1

Answer:

22

$22 {m}^{3}$

Step-by-step explanation:

hope this helps you good luck

Answer 2

(b)22 cu.m

Step-by-step explanation:

Depth of bucket=h=3 m

Upper diameter of bucket=$d_1=4 m$

Upper radius of bucket=$r_1=\frac{d_1}{2}=\frac{4}{2}=2 m$

Lower diameter of bucket=$d_2=2 m$

Lower radius of bucket=$r_2=\frac{d_2}{2}=\frac{2}{2}=1 m$

Volume of bucket=Volume of frustum=$\frac{1}{3}\pi h(r^2_1+r^2_2+r_1r_2)$

Where h=Height of frustum

$r_1$=Radius of upper part

$r_2$=Radius of lower part

$\pi=\frac{22}{7}$

Using the formula

Volume of bucket=$\frac{1}{3}\times \frac{22}{7}\times 3(2^2+1^2+2\times 1)$

Volume of bucket=$22m^3$

Hence,option (b) is true.

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