Question

An industrial bucket is of deptt 3m with upper and lower the metres as 4 m and 2m respectively the amount of water it can hold is

Answer 1

Answer:

Step-by-step explanation:

H=3m

R=4m

r=2m

Volume of frustum=1÷3×π×H(R^2+r^2+Rr)

=1÷3 ×22÷7×3[(4)^2+(2)^2+4×2]= 22÷7(16+4+8)

=22÷7×28

=88m^3