Question

An industrial consumer has a load pattern of 2000 kw 0.8 lag for 12 hours and 1000 kw unity power factor for 12 hours. what is the load factor?

Answer 1

Answer:0.75

Explanation:

Load factor= Average Load/(Maximum demand)

Average load=(2000+1000)/2 =1500

Maximum demand = 2000

Answer 2

As a result, the load factor for the industrial consumer is one.

As per the question given,

The load factor of an industrial consumer can be calculated as the ratio of the average load over a period of time to the maximum load over the same period of time.

In this case, the consumer has a load pattern of 2000 kW for 0.8 lag for 12 hours, and 1000 kW for unity power factor for 12 hours. The total energy consumed during this period can be calculated as:

Energy = (2000 kW * 12 hours * 0.8) + (1000 kW * 12 hours)

= 19200 kWh

The maximum load over the same period of time can be calculated as:

Maximum Load = Maximum of (2000 kW * 0.8) and (1000 kW)

= 2000 kW * 0.8 = 1600 kW

The average load over the period of time can be calculated as:

Average Load = Energy / (12 hours)

= 19200 kWh / (12 hours)

= 1600 kWh

The load factor can be calculated as:

Load Factor = Average Load / Maximum Load

= 1600 kWh / 1600 kW

= 1

So, the load factor for the industrial consumer is 1. This means that the consumer is using its maximum power capacity continuously over a 24-hour period.

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