An industrial designer wants to determine the average amount of time an adults take to assemble an"easy to assemble"toy.a sample of 16 times yielded an average time of 19.92 minutes,with a sample standard deviation of 19.92 minutes,with a sample standard deviation of 5.73 minutes. assuming normality of assembly times, provide a 95% confidence interval for the mean assembly time and interpret the results.
Answers
95% confidence interval for the mean assembly time is [16.87 minutes , 22.97 minutes].
Step-by-step explanation:
We are given that an industrial designer wants to determine the average amount of time an adults take to assemble an "easy to assemble" toy.
A sample of 16 times yielded an average time of 19.92 minutes, with a sample standard deviation of 5.73 minutes.
Firstly, the Pivotal quantity for 95% confidence interval for the population mean is given by;
P.Q. = ~
where, = sample average time = 19.92 minutes
s = sample standard deviation = 5.73 minutes
n = sample size = 16
= population mean assembly time
Here for constructing 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.
So, 95% confidence interval for the population mean, is ;
P(-2.131 < < 2.131) = 0.95 {As the critical value of t at 15 degree
of freedom are -2.131 & 2.131 with P = 2.5%}
P(-2.131 < < 2.131) = 0.95
P( < < ) = 0.95
P( < < ) = 0.95
95% confidence interval for = [ , ]
= [ , ]
= [16.87 , 22.97]
Therefore, 95% confidence interval for the mean assembly time is [16.87 minutes , 22.97 minutes].
Now, the interpretation of the above confidence interval is that we are 95% confident that the mean assembly time will lie between 16.87 minutes and 22.97 minutes.