Question

An industrial load consists of the following:
(a) a load of 200 kVA at 0.8 power factor lagging,
(b) a load of 50 kW at unity power factor,
(c) a load of 48 kW at 0.6 power factor leading.
Calculate the total kW, total kVAr, total kVA and the overall power factor.​

Answer 1

Answer:

By convention. Q is taken positive and negative.

Load a

cos ,-0.8, sin o,-0.6

S-S-S (cos+j sin ) - 200 (0.8+0.6) (160+120) kVA

cos 0 = 1, sin 0,0

Load b

196

NETWORKS AND SYSTEMS

50-51, 5-50 kVA

S-S (sin ) 50 (1-0)-50j0kVA

cos c 0.6, sin 0.8

P = S, cos

48 48-5,0.6.5, = 80 kVA 0.6

Since the power factor cos , is leading. Qe will be negative

therefore,

Total complex power

S, 5,- S, (cos, -j sin c)

80 (0.6-0.8) (48-64) KVA

= 160+j120

+50 +70

+48 +64

-258+56=264 / 12.246 kVA

S-264 kVA

P-258 kW

Q-56 kVAr (lagging)

0=12.246

Load e

Also,

therefore,

Overall power factor, como cos 12.2460.9772 (lagging) It is to be noted that the overall power factor is lagging because the overall Q is positive and by convention lagging Q is taken positive

Explanation:

You can refer to the photo if you are not able to get solution.