An industrial water shutoff valve is designed to operate with 30lbs of effort force. The valve will encounter 200lbs of resistance force applied to a 1.5 in. diameter axle.
Sketch and annotate the wheel and axle systems described above.
Also, what is the required wheel diameter to overcome the resistance force?
Answers
Answer:Sketch and annotate the lever system described above. 2. What is ... wheel? An industrial water shutoff valve is designed to operate with 30 lb of effort force. The valve will encounter 200 lb of resistance force applied to a 1.5 in. diameter axle. 11. ... What is the required wheel diameter to overcome the resistance force
Explanation:
hope this helps
Answer:
Dr= .225
AMA = 6.67
Explanation:
First you have to break it down and find the variables, (Fe, Fr, De,) you are not given Distance resistance (Dr) which is the diameter of the wheel. The Distance Effort (De) is the axle diameter, 1.5in. The Force effort (Fe) is the amount of force used to make it move, 30lb. The Force resistance (Fr) is the force that goes against it, 200lb. To find the diameter of the wheel use the formula Fe x De= Fr x Dr, substitute the variables to your numbers, 30lb x 1.5in = 200lb x (Dr). Multiply 30lb by 1.5in to get 45 = 200lb (Dr). divide 200 by 45 to get .225 | Dr= .225 | To get Actual Mechanical Advantage (AMA) just divide Fr by Fe to get 6.67.