Question

An infinite straight conductor carrying current 2 I is split into a loop of radius r as shown in fig. The magnetic field at the centre of the coil is
(a) $\frac{\mu_{0}}{4\pi}\frac{2(\pi+1)}{r}$
(b) $\frac{\mu_{0}}{4\pi}\frac{2(\pi-1)}{r}$
(c) $\frac{\mu_{0}}{4\pi}\frac{(\pi+1)}{r}$
(d) zero

Answer 1

sorry this video is not a coenicidence you are not a problem with a good day to do the same the

Answer 2

Answer:

$\scriptsize\mathtt \purple{=\frac{1}{4 \pi \varepsilon_{0}} \frac{q_{1}}{r_{1 p }^{2}} \hat{ r }_{1 P }+\frac{1}{4 \pi \varepsilon_{0}} \frac{q_{2}}{r_{2 P }^{2}} \hat{ r }_{2 P }+\ldots .+\frac{1}{4 \pi \varepsilon_{0}} \frac{q_{n}}{r_{n P }^{2}} \hat{ r }_{n P }}$