Physics, asked by 7014053507vy, 10 months ago

An infinitely large thin dielectric sheet of positive
charge has area density of charge σ. If point A is at
distance a and point B at distance 3a from this sheet
then potential difference between B and A, VB - VA
will be​

Answers

Answered by JackelineCasarez
0

2σa/E_{0}

Explanation:

Given that,

Infinite Large Thin dielectric sheet has +ve charge

Distance at point A = a

Distance at point B = 3a

As we know,

V = E * d

E = σ/E_{0}

∴ V = σ/E_{0} * d

V_{B} = (σ * 3a)/E_{0}

V_{A} = (σ * a)/E_{0}

Thus,

V_{B} - V_{A} = [(σ * 3a)/E_{0}] - [ (σ * a)/E_{0} ]

= 2σa/E_{0}

Thus, 2σa/E_{0} is the difference between V_{B} - V_{A}.

Learn more: Potential Difference

brainly.in/question/11671

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