Question

An infinitely long cylindrical conductor of radius 15 cm has a linear charge density (charge per unit length) of 3 x 10- 9 cm- 1 . Determine the electric field due to the conductor at a point at a distance 30 cm perpendicular to its axis

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Answer 1

Answer:

The electric field due to the conductor at a point at a distance 30 cm perpendicular to the axis is 180 N/C

Explanation:

Here we have a long conducting cylindrical wire

If the charge density of the wire is given as

$\lambda = 3 \times 10^{-9} c/m$

Now we can use Gauss law to find the electric field due to long wire

here we will assume a Gaussian surface of cylindrical shape with radius 30 cm

now we have

$\int E. dA = \frac{q_{en}}{\epsilon_0}$

$E(2\pi r L) = \frac{Q}{\epsilon_0}$

now we will have

$E = \frac{\lambda}{2\pi \epsilon_0 r}$

now we have

$E = \frac{2(3 \times 10^{-9}) (9 \times 10^9)}{0.30}$

$E = 180 N/C$

#Learn

Topic : Gauss Law

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