Question

An infinitely long solid cylinder of radius R has a uniform
volume charge density p. It has a spherical cavity of
radius R/2 with its centre on the axis of the cylinder, as
shown in the figure. The magnitud of the electric field at
the point P, which is at a distance 2R from the axis of the
33PR
cylinder, is given by the expression 16k. The value of
k is
[AIIMS]​

Answer 1

Answer: 6

Explanation:We suppose that the cavity is filled up by a positive as well as negative volume charge of r. So the electric field now produced at P is the superposition of two electric fields.

(i) The electric field created due to the infinitely long solid cylinder is E1=ρR4ε0

E1=ρR4ε0

directed towards the +Y direction

(ii) The electric field created due to the spherical negative charge density E1=ρR96ε0E1=ρR96ε0 directed towards the -Y direction.

∴∴ The net electric field is

E=E1−E2

=16[23ρR16ε0]

Answer 2

Answer:

Explanation:

I dont know !!

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