Question

An initial gas possesses an initial pressure of 200 N per square meter at a temperature of 1000 Kelvin. while holding the volume constant the temperature decreases to 400 Kelvin. what is the resultant pressure. ​

Answer 1

Given:

• Initial pressure(p1) = 200 N/ m².

• Final pressure(p2) =?

• Initial temperature(T1) = 1000 K

• Final temperature(T2) = 400 K

• Initial volume = v1

• Final volume = v2.

• Volume remains constant.

To find:

The resultant pressure(p2).

Solution:

Since the volume remains constant through out the process so,

v1= v2.

From the ideal gas law equation we get that,

$\dfrac{p1v1}{T1} = \dfrac{p2v2}{T2}$

Here,

$\dfrac{p1v1}{T1} = \dfrac{p2v2}{T2}$

$or, \dfrac{p1}{T1} = \dfrac{p2}{T2} [ v1 = v2]$

$or, \dfrac{200}{1000} = \dfrac{p2}{400}$

$or, \dfrac{1}{5} = \dfrac{p2}{400}$

$or, \dfrac{p2}{400} = \dfrac{1}{5}$

$or, p2 = \dfrac{400}{5}$

or, p2 = 80 N/m².

So, the resultant pressure is 80 N/m².

Answer:

              The resultant pressure is 80 N/m².