Question

An initially stationary device lying on a frictionless floor explodes into two pieces and slides across the floor one
piece is moving in positive x direction then other peice is moving in​

Answer 1

answer : negative direction of x - axis.

explanation : we know, when external force acting on a system of bodies is zero, then linear momentum of system remains constant.

i.e., initial linear momentum of system = final linear momentum of system.

here, an initially stationary device lying on a frictionaless floor.

so, initial velocity ,u = 0

so, initial linear momentum = mu = 0

The device is explode into two pieces and slide across the floor. let mass of one price is M1 and other pieces is M2

a/c to question, one piece is moving positive x - direction.

now final linear momentum = M1v1 + M2v2

there is no external force acting on system.

so, initial linear momentum = final linear momentum

or, 0 = m1v1 + m2v2

or, m1v2 = -m2v2

hence, it is clear that if one piece moves in positive direction then other piece must be moved in negative direction of x-axis

Answer 2

Answer:

Answer is " Negative x direction"

Explanation:

see the uploaded photo