Question

An inorganic salt on the analysis gave the following percentage composition ; Pb = 62.6 % , N = 8.4% , O = 29% . What is empirical formula of the compound ? At. mass Pb = 207, N = 14 , O = 16)

Answer 1

Dude, take the ratio of the percentage and the atomic mass of the element

62.6/207 = 0.3 approx

8.4/14 = 0.6

29/16 = 1.8

So, the ratio is: 0.3 : 0.6 : 1.8

when you simplify, you'll get 1 : 2 : 6

so, the formula is: PbN₂O₆

The actual formula is: Pb(NO₃)₂

please mark me brainliest

Answer 2

Answer:

The empirical formula of the compound is PbN₂O₃.

Explanation:

 From the given data,

      $Element\\ \\ Pb\\ N\\ O$     $Atomic \\ mass\\ 207.2\\ 14\\ 16$       $Percentage\\ \\ 62.6\\ 8.4\\ 29$    $Moles\\ \\ 0.30\\ 0.6\\ 1.81$       $Simplest\\ Ratio\\ 1\\ 2\\ 3$

Therefore, the empirical formula of the compound is PbN₂O₃.