An inorganic substance on analysis gave the following results Na= 29.1% , S =40.5% and O=30.4%. calculate its empirical formula
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An inorganic substance on analysis gave the following results Na = 29.1%, S = . 40.5% and O = 30.4%. ... Simplest whole number ratio of Na :S: O will be 2:2: 3 and thus empirical formula will be Na2S2O3.
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