An inorganie salt on analysis gave the following percentage composition : Pb 62.6, N = 8.4 = 29 O = 29. What is empirical formula of the compound ? Also name the compound.
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Step-by-step explanation:
atoms of Pb : N : O = 62.6/207 : 8.4/14 : 29/16 =0.30 : 0.6 : 1.8 = 1: 2 :6. Hence the empirical formula is PbN2O6.
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