Question

An insect climbs 4 cm up on a slippery rod in 2 sec and slips down by2 cm over the
next one second. How many minutes will the insect take to reach rod 20 cm high?

Answer 1

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Answer 2

Answer:

It takes (1/2) or 0.5 min. to climb the 20 cm high rod.

Step-by-step explanation:

We are given,

An insect climbs 4 cm up on a slippery rod in 2 sec and slips down by 2 cm over the next one second.

Thus,

In the 1st 2 seconds the insect climbs up 4 cm

Next, in 1 second it slips down by 2 cm

Hence, Total distance covered = 4 - 2 = 2 cm

Total time taken = 2 + 1 = 3 seconds

So, it covers 2 cm in 3 secs

Then, it must be proportional, right?!!!

Then, it must be proportional, right?!!!Now, Let the time taken to climb 20cm be 'x' seconds

Therefore,

Therefore, 2 : 3 :: 20 : x

We know that,

We know that,Product of extremes = Product of means

We know that,Product of extremes = Product of means2 × x = 3 × 20

We know that,Product of extremes = Product of means2 × x = 3 × 202x = 60

We know that,Product of extremes = Product of means2 × x = 3 × 202x = 60x = 60/2

We know that,Product of extremes = Product of means2 × x = 3 × 202x = 60x = 60/2x = 30 secs

We know that,Product of extremes = Product of means2 × x = 3 × 202x = 60x = 60/2x = 30 secsThus, it takes 30 seconds for the insect to climb 20cm high rod.

But, remember the Question asks us to find the minutes it take

But, remember the Question asks us to find the minutes it take 1 min. = 60 sec.

But, remember the Question asks us to find the minutes it take 1 min. = 60 sec.1 sec. = (1/60) min.

But, remember the Question asks us to find the minutes it take 1 min. = 60 sec.1 sec. = (1/60) min.Thus,

But, remember the Question asks us to find the minutes it take 1 min. = 60 sec.1 sec. = (1/60) min.Thus,30 sec. = 30 × (1/60)

But, remember the Question asks us to find the minutes it take 1 min. = 60 sec.1 sec. = (1/60) min.Thus,30 sec. = 30 × (1/60)= (1/2) min. or 0.5 min.

But, remember the Question asks us to find the minutes it take 1 min. = 60 sec.1 sec. = (1/60) min.Thus,30 sec. = 30 × (1/60)= (1/2) min. or 0.5 min.Thus, it takes (1/2) or 0.5 min. to climb the 20 cm high rod.

Now, you might think this is the answer, but it is not.

Let's see in the 27th second, the insect would cover,

2 × 27 = 3 × x

3x = 54

x = 54/3

x = 18 m

Thus, at the 27th second, the insect has already reached 18m because in the last second it slipped down 2 cm.

Thus, at 26th second he already reached the top of the rod.

Thus, it took 26 seconds to to reach the rod

In2sinsect econds the

But again, ni the 28th second it would go 4cm above ag

Thus, it has already crossed 20 cm and reached the top.

Hence, if the Question is asking

Hope it helped and you understood it........All the best