An insect crawl a distance of 4m long north in 10sec and then distance of 3m along east in 5sec average velocity
Answers
Answered by
28
avg. velocity = displacement / time
displacement = √(3² + 4²)
=5
avg .velocity = 5/15
=.333
displacement = √(3² + 4²)
=5
avg .velocity = 5/15
=.333
Answered by
5
Answer:
avg. velocity = displacement / time
displacement = √(3² + 4²)
=5
avg .velocity = 5/15
=.333
Explanation:
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