Question

An insect crawls up 5 cm every second on a 60 cm vertical rod and then falls down 2 cm over the next second. How many seconds will it take to climb the rod?​

Answer 1

${\pmb{\underline{\sf{ Required \ Solution ... }}}}$

As We know that An insect crawls tried to stepping of the Vertical Rod of length of 60 cm.

An Insect crawls up 5 cm every second on the Vertical Rod.

» +5 cm/sec

As We also know that with the crawling of vertical rod, an Insect falls down 2 cm over every next second of crawling.

» -2 cm/sec

Now, We should add both the Phenomena performed by an Insect during climbing of Vertical Rod as.

» (+5 + (-2))cm

» (+5-2)cm

» 3 cm/sec

As We got that An Insect will cover only 3 cm in Every second of crawling a Vertical Rod.

We should mind the Length of the Vertical Rod is 60 cm and We can get the time taken by an Insect to climb the Vertical Rod by Dividing with steps taken out with An Insect Every second.

$\colon\implies{\sf{ \dfrac{60}{3} }} \\ \\ \colon\implies{\sf{ 20 \ sec }}$

Hence,

We got that An Insect has taken 20 seconds to climb the Vertical Rod.