Question

an insect craws a distance of 3m along northin 6 second and then a distanceof 4m along east in 9sec.then the average velocity of the insect is

Answer 1

total displacement= √(3^2 + 4^2)
= √(9+16)
=√25
= 5
Average velocity = displacement ÷ time
= 5 ÷ (6+9)
= 5 ÷ 15
= 1÷3m