Math, asked by shaikhuzaifa33, 5 months ago

An insect moves 3m east, 4m north
and 5m vertically up. Displacement
covered by insect is
5m
52m
2m
7 m​

Answers

Answered by devintarajan1981
1

Answer = 7 meters......

Answered by gayatrikumari99sl
0

Answer:

5\sqrt{2} m is the displacement covered by the insect .

Step-by-step explanation:

Explanation:

Given , an insect moves 3m east , 4m north and 5m vertically up

Let  East direction be along i ̂  , North direction be  j ̂  and

Let  k ̂   be the vertically upward direction .

Therefore , the position vector  = 3i ̂ +  4 j ̂  +5( k) ̂

Step 1:

By distance  of the insects from the origin = |\vec{r}|

⇒|\vec{r}|  = \sqrt{3^{2}  + 4^{2}  + 5^{2} } = \sqrt{9 + 16 + 25} = \sqrt{50}

⇒|\vec{r} |= 5\sqrt{2}m

Final answer:

Hence , displacement covered by insect is 5\sqrt{2} m

#SPJ3

Similar questions