Question

An insect moves 3m east, 4m north
and 5m vertically up. Displacement
covered by insect is
5m
52m
2m
7 m​

Answer 1

Answer = 7 meters......

Answer 2

Answer:

$5\sqrt{2}$ m is the displacement covered by the insect .

Step-by-step explanation:

Explanation:

Given , an insect moves 3m east , 4m north and 5m vertically up

Let  East direction be along i ̂  , North direction be  j ̂  and

Let  k ̂   be the vertically upward direction .

Therefore , the position vector  = 3i ̂ +  4 j ̂  +5( k) ̂

Step 1:

By distance  of the insects from the origin = |$\vec{r}$|

⇒|$\vec{r}$|  = $\sqrt{3^{2} + 4^{2} + 5^{2} }$ = $\sqrt{9 + 16 + 25}$ = $\sqrt{50}$

⇒|$\vec{r}$ |= $5\sqrt{2}$m

Final answer:

Hence , displacement covered by insect is $5\sqrt{2}$ m

#SPJ3