Question

an insect moves along a circular path of radius 10 cm with a constant speed it takes 1 minute to move from a point on the path to the diametrically opposite point . Find a) the distance covered b) the displacement c) The average velocity

Answer 1

distance = 10*3.14=31.4 cm.
speed=31.4/(60*100) = 0.00523 m/s = 0.523 cm/s.
displacement = 10 cm,
velocity = 1/6 cm/s.

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Answer 2

Concept:

• Circular motion
• Vector and scalar quantities
• Difference between speed and velocity
• Difference between distance and displacement

Given:

• The radius of circular path R = 10 cm
• time taken for the insect to move from the initial point to a point diametrically opposite to it t = 1 min = 60 s

Find:

• The distance covered by the insect
• The displacement of the insect
• The average velocity of the insect.

Solution:

The insect moves along the circular path from one point to a diametrically opposite point.

a) So the distance it covers = 2πR/2 = πR

Distance = πR = π* 10 = 10π cm = 31.4 cm

b) The shortest distance between the final and initial point is the displacement and in this case the shortest distance between the final and initial point is the diameter of the circular path

Displacement = D = 2R = 2 (10) = 20 cm

c) The average velocity is the value of the displacement per unit of time.

v = displacement/time

v = 20 cm/ 60 s = 1/3 cm/s = 0.33 cm/s

The distance covered is 31.4 cm.

The displacement is 20 cm.

The average velocity is 0.33 cm/s.

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