Question

An insect's moves 3cm north 4m east and 5m vertically up then the resultant displacements
Is

Answer 1

Answer:

The displacement is 15.52 m.

Explanation:

Given that,

A insect moves 3 m north, then 4 m east, and then 12 m vertically upwards as show in the figure

The displacement is the change in the position of the particle from initial position to final position.

According to figure,

The resultant displacement is defined as:

$D=\sqrt{(0-4)^2+(0-15)^{2}} \\ </p><p>D = \sqrt{(-4)^2+(-15)^2} \\ </p><p>D= \sqrt{241} \\ </p><p>D = 15.52\ m$

Hence, The displacement is 15.52 m.

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Answer 2

Answer:

Displacements is 6.403 m

Explanation:

Displacement is defined as the change in the position  of the object

Insect moves north is 3cm = 0.03m

Towards east  =  4m

vertically up   =  5m

Displacement = √4²₊0.03²₊5²

                      = √16+0.0009+25

                     =√41.0009

                     =6.40 m