Question

An insect starts climbing a wall 12 feet high at 11 a.m. Every minue it ascends one foot. But descends 6 inches at what time will it reach the top?​

Answer 1

Answer:

If it climbs 10 feet then stops and slides down 1/2 a foot and then starts uo again, we would need the amount of time for the 6-inch slide to solve this problem. If the climb and slippage occur at the same time the bug’s actual ascent rate would be 9.5 feet per second. At 9.5 feet per second, it would take 10.526… to cover 10 feet. So the time would be 10:00:01.516 a.m.

Step-by-step explanation:

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